Ta có: \(3^{2n}+1+2^{n+2}=9^n.3+1+2^n.4\)
\(=9^n.3+1-2^n.3+2^n.7\)
\(=3\left(9^n-2^n\right)+1+2^n.7\)
Do \(9^n-2^n⋮9-2=7\)\(\Rightarrow3\left(9^n-2^n\right)+1⋮7\)\(;2^n.7⋮7\)
\(\Rightarrow3\left(9^n-2^n\right)+1+2^n.7⋮7\Rightarrow3^{2n}+1+2^{n+2}⋮7\)