Ta có ; \(\frac{a}{b}=\frac{c}{d}\Rightarrow\frac{a}{c}=\frac{b}{d}=\frac{5a}{5c}=\frac{3b}{3d}=\frac{5a+3b}{5c+3b}=\frac{5a-3b}{5c-3b}\)
Nên : \(\frac{5a+3b}{5c+3d}=\frac{5a-3b}{5c-3d}\)
Vậy \(\frac{5a+3b}{5a-3b}=\frac{5c+3d}{5c-4d}\left(đpcm\right)\)
\(cho\frac{a}{b}=\frac{c}{d}CMR\frac{5a+3b}{5a-3b}=\frac{5c+3d}{5c-3d}\)
Chứng minh rằng: Nếu \(\frac{a}{c}=\frac{b}{d}\)thì \(\frac{5a+3b}{5a-3b}=\frac{5c+3d}{5c-3d}\)
Chứng minh rằng nếu
\(\frac{a}{b}=\frac{c}{d}\)thì \(\frac{5a+3b}{5a-3b}=\frac{5c+3d}{5c-3d}\)
Cho \(\frac{a}{b}=\frac{c}{d}\) CMR \(\frac{5a+3b}{5a-3b}=\frac{5c+3d}{5c-3d}\)
CMR nếu a/b=c/d thì : \(\frac{5a+3b}{5a-3b}=\frac{5c+3d}{5c-3d}\)
Cho \(\frac{a}{b}=\frac{c}{d}\). c/m:
a) \(\frac{a}{b}=\frac{a^2+c^2}{b^2+c^2}\)
b) \(\frac{5a+3b}{5a-3b}=\frac{5c+3d}{5c-3d}\)
chứng minh rằng \(\frac{a}{b}=\frac{c}{d}\)thì
\(\frac{5a+3b}{5a-3b}=\frac{5c+3d}{5c-3d}\)
cho \(\frac{a}{b}=\frac{c}{d}\left(c\ne+-\frac{3}{5}d\right)\)
chứng minh \(\frac{5a+3b}{5c+3d}=\frac{5a-3b}{5c-3d}\)
Chứng minh:\(\frac{5a+3b}{5c+3d}=\frac{2a-3b}{2c-3d}\) Cho a/b=c/d.
