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14 tháng 7 2015 lúc 22:12
Cho \(\frac{2a+b+c+d}{a}=\frac{a+2b+c+d}{b}=\frac{a+b+2c+d}{c}=\frac{a+b+c+2d}{d}\)
Tính \(M=\frac{a+b}{c+d}+\frac{b+c}{d+a}+\frac{c+d}{a+b}+\frac{d+a}{b+c}-\left(\frac{a+b}{c+d}+\frac{b+c}{d+a}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\right)\)
cho \(\frac{a}{b+c+d}=\frac{b}{a+c+d}=\frac{c}{a+b+d}=\frac{d}{a+b+c}\)
tính \(A=\frac{a+b}{c+d}+\frac{b+c}{a+d}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
Cho \(\frac{a}{b+c+d}=\frac{b}{a+c+d}=\frac{c}{a+b+d}=\frac{d}{a+b+c}\) . Tính
\(M=\frac{a+b}{c+d}+\frac{b+c}{a+d}+\frac{c+d}{a+b}+\frac{a+d}{b+c}\)
cho \(\frac{a}{b+c+d}=\frac{b}{a+c+d}=\frac{c}{a+b+d}=\frac{d}{a+b+c}\)
tính M=\(\frac{a+b}{c+d}+\frac{b+c}{a+d}+\frac{c+d}{a+b}=\frac{a+d}{b+c}\)
1.Cho a+b+c+d ≠0 và frac{a}{b+c+d}frac{b}{a+c+d}frac{c}{a+b+d}frac{d}{a+b+c}Tính giá trị của Afrac{a+b}{c+d} +frac{b+c}{a+d}+frac{c+d}{a+b}+frac{d+a}{b+c}2.Tìm x,y,z biết :a)dfrac{x^3}{8}dfrac{y^3}{64}dfrac{z^3}{216}và x^2+y^2+z^214b)dfrac{2x+1}{5}dfrac{3y-2}{7}dfrac{2x+3y-1}{6x}
Đọc tiếp
1.Cho a+b+c+d ≠0 và \(\frac{a}{b+c+d}\)=\(\frac{b}{a+c+d}\)=\(\frac{c}{a+b+d}\)=\(\frac{d}{a+b+c}\)
Tính giá trị của A=\(\frac{a+b}{c+d} \)+\(\frac{b+c}{a+d}\)+\(\frac{c+d}{a+b}\)+\(\frac{d+a}{b+c}\)
2.Tìm x,y,z biết :
a)\(\dfrac{x^3}{8}\)=\(\dfrac{y^3}{64}\)=\(\dfrac{z^3}{216}\)và \(x^2\)+\(y^2\)+\(z^2\)=14
b)\(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
Cho \(a+b+c+d\ne0\)sao cho \(\frac{a}{b+c+d}=\frac{b}{a+c+d}=\frac{c}{a+b+d}=\frac{d}{a+b+c}\)Tính\(G=\frac{a+b}{c+d}+\frac{b+c}{a+d}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
Cho: \(\frac{2a+b+c+d}{a}=\frac{a+2b+c+d}{b}=\frac{a+b+2c+d}{c}=\frac{a+b+c+2d}{d}\)
Tính M= \(\frac{a+b}{c+d}=\frac{b+c}{d+a}=\frac{c+d}{a+b}=\frac{d+a}{b+c}\)
1.Cho
\(\frac{a}{b+c+d}=\frac{b}{a+c+d}=\frac{c}{a+b+d}=\frac{d}{a+b+c}\)tính \(M=\frac{a+b}{c+d}+\frac{b+c}{a+d}=\frac{c+d}{a+b}=\frac{d+a}{b+c}\)
Cho dãy tỉ số bằng nhau :
a) \(\frac{a+b+c-d}{d}=\frac{b+c+d-a}{a}=\frac{c+d+a-b}{b}=\frac{d+a+b-c}{c}\)
Tính : \(M=\frac{a+b}{c+d}+\frac{b+c}{d+a}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
Cho 4 số a,b,c,d sao cho:
\(\frac{a}{b+c+d}=\frac{b}{a+c+d}=\frac{c}{a+b+d}=\frac{d}{a+b+c}\)
Tính A = \(\frac{a+b}{c+d}+\frac{b+c}{a+d}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
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