áp dụng tc dãy tc = nhau ta có:
x-2/2=y-3/3=x-2+y-3/2+3=x+y-2-3/5=10-5/5=5/5=1
=>x-2/2=1=>x-2=2=>x=4
=>y-3/3=1=>y-3=3=>y=6
vậy x.y=4.6=24
\(\frac{x-2}{2}=\frac{y-3}{3}=\frac{x-2+y-3}{2+3}=\frac{x+y-5}{5}=\frac{10-5}{5}=1\)
=> x- 2=2 ; y-3=3
=> x = 4 ; y=6
=> xy = 24