Ta có: \(\widehat{M}+\widehat{N}+\widehat{P}+\widehat{Q}=360^0\)
\(\Leftrightarrow\widehat{M}+\left(\widehat{M}-10^0\right)+70^0+65^0=360^0\)
\(\Leftrightarrow\widehat{M}+\widehat{M}-10^0+70^0+65^0=360^0\)
\(\Leftrightarrow M+\widehat{M}-10^0+135^0=360^0\)
\(\Leftrightarrow2\widehat{M}+125^0=360^0\)
\(\Rightarrow M=117,5^0\)
\(\widehat{N}=\widehat{M}-10^0=117,5^0-10^0=107,5^0\)