Đặt \(\frac{c+d}{d+a}=\frac{a+b}{b+c}=k\)
\(\Rightarrow\hept{\begin{cases}c+d=\left(d+a\right)k\\a+b=\left(b+c\right)k\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}c+d=dk+ak\\a+b=bk+ck\end{cases}}\)
\(\Rightarrow a+b+c+d=bk+ck+dk+ak\)
\(\Rightarrow a+b+c+d=\left(a+b+c+d\right)k\)
\(\Rightarrow k=1\)
\(\Rightarrow\hept{\begin{cases}c+d=d+a\\a+b=b+c\end{cases}}\)
\(\Rightarrow c+d-d-a=0\)
\(\Rightarrow c-a=0\)
\(\Rightarrow c=a\)