Ta có: \(tan\widehat{CAB}=\frac{BC}{AB}\Leftrightarrow tan30^0=\frac{BC}{4\sqrt{3}}\)
\(\Leftrightarrow\frac{\sqrt{3}}{3}=\frac{BC}{4\sqrt{3}}\Leftrightarrow BC=4\) (cm)
\(S_{ABC}=\frac{1}{2}BC\cdot BA=\frac{1}{2}\cdot4\cdot4\sqrt{3}=8\sqrt{3}\) (cm2)
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