Xét 2 tam giac BHE = BHA ( canh huyen - goc nhon ) => EB=AB; HE=HA
Xet 2 tam giac HCE = AHI ( g-c-g) => CE = AI
Ta co: CE+EB=CB
IA+AB= IB
Mả CE=AI; EB= AB => CB+IB
Xet 2 tam giac CMB= IMB (c-g-c) ( M la giao diem cua BH va CI)
=> goc CMB=goc IMB
MA CMB + IMB =180 (ke bu)
=> goc CMB=IMB=90
=> BH vuong goc vs IC
Nhan xet : tam giac IBC can vi BC = BI