Ta có: \(BC=BH+HC=9+16=25cm\)
Xét \(\Delta ABC\perp A\) có:
\(AB^2=BC.BH\)
\(\Leftrightarrow AB^2=9.25=225\)
\(\Rightarrow AB=\sqrt{225}=15cm\)
\(AH^2=BH.HC\)
\(\Leftrightarrow AH^2=9.16\)
\(\Leftrightarrow AH^2=144\)
\(\Rightarrow AH=\sqrt{144}=12cm\)
\(AC^2=BC.HC\)
\(\Leftrightarrow AC^2=25.16\)
\(\Leftrightarrow AC^2=400\)
\(\Rightarrow AC=\sqrt{400}=20cm\)