Vì MN || AB nên MN AC tại M. Tứ giácMNAB là hình thang vuông. Nối NA. Từ N hạ NH AB thì NH là chiều cao của tam giác NBA và của hình thang MNBA nên NH = MA và là 9 cm. Diện tích tam giác NBA là : 28 x 9 : 2 = 126 (cm2 ) Diện tích tam giác ABC là : 36 x 28 : 2 = 504 (cm2 ) Diện tích tam giác NAC là : 504 – 126 = 378 (cm2 ) Đoạn MN dài là : 378 x 2 : 36 = 21 (cm)
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bạn Trần Phương Linh người ta không biết thì hỏi có gì sai
Nối A với N . Ta có tam giác NCA có MN là chiều cao , vì MN // AB nên MN cũng vuông góc với CA
Diện tích tam giác NCA là :
32 x 16 : 2 = 256 (cm2)
Diện tích tam giác ABC là :
24 x 32 : 2 = 384 ( cm2)
Diện tích tamn giác NAB là :
384 - 256 = 128 ( cm2)
Chiều cao NK hạ từ đỉnh N xuống cạnh AB dài :
128 x 2 : 24 = 10\(\frac{2}{3}\) cm
Vì MN // Ab nên tứ giác MNBA là hình thang vuông . Vậy NK cũng là chiều cao của hình thang MNBA . Do đó MA cũng bằng 10\(\frac{2}{3}\) cm
cái này lơp 1 vân làm đươc nhé
ài ày ẽ
···
Trần Phương Linh bn lm như lm gỏi lém ý
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Diện tích tam giác ABC là:
32×24:2=38432×24:2=384 (cm2cm2 )
Diện tích tam giác ACN là:
32×16:2=25632×16:2=256 (cm2cm2 )
Diện tích tam giác ANB là:
384−256=128384−256=128 (cm2cm2 )
Tỉ số diện tích tam giác ABC và diện tích tam giác ANB là:
384:128=3384:128=3
Xét tam giác ABC và ANB có chung đáy AB, diện tích tam giác ABC gấp 33 lần điện tích tam giác ANB nên chiều cao AC gấp 33 lần MA.
Độ dài đoạn MA là:
32:3=323=10,66732:3=323=10,667 (cm)
ĐS: 10,66710,667 cm
ht
10 và 2/3 ( bạn viết kết quả dưới dạng hỗn số nha )
đúng 100% luôn
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lên google mà hỏi :)))))
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