Ta có:\(3A=2C\Rightarrow A=\frac{2}{3}C\)
Xét tam giác ABC:
\(A+B+C=180^o\)
\(\Rightarrow\frac{2}{3}C+80^o+C=180^o\)
\(\Rightarrow\frac{2}{3}C+1C=100^o\)
\(\Rightarrow\left(\frac{2}{3}+1\right)C=100^o\)
\(\Rightarrow\frac{5}{3}C=100^o\)
\(\Rightarrow C=100^o:\frac{5}{3}=60^o\)
\(A=\frac{2}{3}C=\frac{2}{3}.60^o=40^o\)