Question

Cho \(S\) = \(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{99.101}\)

Khi đó \(2S+\frac{1}{101}=\)

Answer 1

\(2S=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+.........+\frac{1}{99}-\frac{1}{101}=1-\frac{1}{101}\)

\(2S+\frac{1}{101}=1-\frac{1}{101}+\frac{1}{101}=1\)

Answer 2

Nguyễn Nhật Minh đúng rồi

Answer 3

2S+\(\frac{1}{100}\)=1

Cho minh vai li-ke cho tron 130 nha