Bài 4: Giải các phương trình sau
a) 4(x+5)(x+6)(x+10)(x+12)=\(3x^2\)
b) \(\frac{1}{x^2-3x+3}+\frac{2}{x^2-3x+4}=\frac{6}{x^2-3x+5}\)
c) \(\frac{4x}{4x^2-8x+7}+\frac{3x}{4x^2-10x+7}=1\)
d) \(\dfrac{2x}{2x^2-5x+3}+\dfrac{13x}{2x^2+x+3}=6\)
Bài 4: Giải các phương trình sau
a) 4(x+5)(x+6)(x+10)(x+12)=\(3x^2\)
b) \(\frac{1}{x^2-3x+3}+\frac{2}{x^2-3x+4}=\frac{6}{x^2-3x+5}\)
c) \(\frac{4x}{4x^2-8x+7}+\frac{3x}{4x^2-10x+7}=1\)
d) \(\frac{2x}{2x^2-5x+3}+\frac{13x}{2x^2+x+3}\)
Phân tích đa thức thành nhân tử
a) \(\left(x+y\right)\left(x+2y\right)\left(x+3y\right)\left(x+4y\right)+x^4\)
b) \(\left(x^2+4x+2\right)^2-3x\left(x^2+4x+2\right)+2x^2\)
c) \(4x^4-8x^3+3x^2-8x+4\)
d)\(2x^4-15x^3+35x^3-30x+8\)
Thực hiện phép tính
a, 4x\(^5\):(2x\(^{^{ }3}\)+6\(^4\)) :(-x\(^4\)) -5x\(^3\):(-2x)\(^2\)
b,(5a\(^2\)y\(^2\)x\(^4\)-10ax\(^3\)y\(^3\)+5a\(^2\)y\(^4\)x\(^2\)):(-5a\(^2\)x\(^2\)y\(^2\)):(x-y)
c, [(4x-y)\(^3\)+3(y-4x)\(^2\)-16x\(^2\)+y\(^2\)] :(y-4x)
giải phương trình
a)\(\left(x+3\right)^2-\left(x-3\right)^2=6x\)
b)\(\frac{x-3}{x-2}=\frac{5}{\left(x-2\right)\left(x+3\right)}\)
c)\(\frac{12x^2-30x-21}{16x^2-9}-\frac{3x-7}{3-4x}=\frac{6x-5}{4x-3}\)
Giải phương trình sau:
a) \(\frac{4}{-25x^2+20x-3}=\frac{3}{5x-1}-\frac{2}{5x-3}\)
b) \(\frac{1}{x^2-3x+2}+\frac{1}{x^2-5x+6}-\frac{2}{x^2-4x+3}\)
c)\(\frac{x-1}{2x^2-4x}-\frac{7}{8x}=\frac{5-x}{4x^2-8x}-\frac{1}{8x-16}\)
d)\(\frac{1}{x^2+9x+20}+\frac{1}{x^2+11x+30}+\frac{1}{x^2+13x+42}=\frac{1}{18}\)
k, \(x^4-7x^{^2}+6\)
l, \(x^4+2x^2-3\)
m, \(4x^2-12x^2-16\)
n, \(x^4+x^2+1\)
s, \(2x^3-35x+75\)
t, \(3x^3-4x^2+13x-4\)
u, \(6x^3+x^2+x+1\)
v, \(4x^3+6x^2+4x+1\)
w, \(x^6-9x^3+8\)
lm giúp mk nha mấy bài này khó quá
Giúp mình với ạ, thanks
\(1,\frac{x-3}{2}+\frac{4x+1}{3}=\frac{2x-7}{6}\)
\(2,\frac{x-4}{5}+\frac{3x-2}{10}-x=\frac{2x-5}{3}-\frac{7x+2}{6}\)
\(3,\frac{2\left(x-3\right)}{4}+\frac{x-5}{3}=\frac{13x+4}{12}\)
Giải các phương trình,bất phương trình:
c,\(\frac{\left(x-2\right)^2}{3}-\frac{\left(2x-3\right)\left(2x+3\right)}{8}+\frac{\left(x-4\right)^2}{6}=0\)
d,\(\frac{4}{-25x^2+20x-3}=\frac{3}{5x-1}-\frac{2}{5x-3}\)
e,\(\frac{1}{x^2-3x+2}+\frac{1}{x^2-5x+6}-\frac{2}{x^2-4x+3}=0\)
g,\(\frac{x-1}{2x^2-4x}-\frac{7}{8x}=\frac{5-x}{4x^2-8x}-\frac{1}{8x-16}\)
h,\(\frac{1}{x^2+9x+20}+\frac{1}{x^2+11x+30}+\frac{1}{x^2+13x+42}=\frac{1}{18}\)
i,\(\left(2x-5\right)^2-\left(x+2\right)^2=0\)
k,\(\left(3x^2+10x-8\right)^2=\left(5x^2-2x+10\right)^2\)
l,\(\left(x^2-2x+1\right)-4=0\)
m,\(4x^2+4x++1=x^2\)
Xin đáy ai giúp mình đi