Ta có : \(x=99\Rightarrow x+1=100\)
\(\Leftrightarrow P\left(99\right)=x^{99}-\left(x+1\right)x^{98}+\left(x+1\right)x^{97}-...+\left(x+1\right)x-1\)
\(\Leftrightarrow x^{99}+x^{98}+x^{97}+...+x^2+x-1\)
\(\Leftrightarrow x-1\) Thay x = 99 vào x - 1 ta có
\(\Leftrightarrow P\left(99\right)=99-1=98\)