\(\frac{8n-3}{2n+1}=\frac{13}{5}\)
\(\Rightarrow\left(8n-3\right)\cdot5=\left(2n+1\right)\cdot13\)
\(\Rightarrow40n-15=26n+13\)
\(\Rightarrow40n-26n=13+15\)
\(\Rightarrow14n=28\)
\(\Rightarrow n=28\div2\)
\(\Rightarrow n=14\)
ta có : 8n-3/2n+1=13/5
(8n-3).5=(2n+1).13
40n-15=26n+13
40n-26n=15+23
14n=28
suy ra n=28:14=2
vậy n=2