P=3+22(2+1)+24(2+1)+26(2+1)
=3(1+22+24+26)\(⋮3\)
=>đpcm
P = 1 + 2 + 22 + 23 + 24 + 25 + 26 + 27
=> P = (1 + 2) + (22 + 23) + (24 + 25) + (26 + 27)
=> P = 1 . 3 + 22 (1 + 2) + 24 (1 + 2) + 26 (1 + 2)
=> P = 1 . 3 + 22 . 3 + 24 . 3 + 26 . 3
=> P = 3(1 + 22 + 24 + 26)
=> P chia hết cho 3
Vậy P chia hết cho 3.
P=3+2^2(2+1)+2^4(2+1)+2^6(2+1)
=3(1+2^2+2^4+2^6)
=>đpcm