Các câu hỏi tương tự
CHO
\(\frac{1}{M}=\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+\frac{1}{1+2+3+4+5}+...+\frac{1}{1+2+3+...+59}\)
Chứng minh rằng M>\(\frac{2}{3}\)
Cho M =\(\frac{1}{1+2+3}\)+\(\frac{1}{1+2+3+4}\)+..............................+\(\frac{1}{1+2+3+..........+59}\)
Chứng minh M<\(\frac{2}{3}\)
\(ChoM+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+....+\frac{1}{1+2+3+4+...+59}.\)
Chứng minh rằng \(M< \frac{2}{3}\)
Cho I frac{1}{4^2}+frac{1}{6^2}+frac{1}{8^2}+...+frac{1}{2006^2}chứng minh: I frac{334}{2007}Cho K frac{1}{5^2}+frac{1}{9^2}+...+frac{1}{409^2}chứng minh: K frac{1}{12}cho M frac{3}{4}+frac{8}{9}+frac{15}{16}+...+frac{2499}{2500}chứng minh: M 48cho N frac{1}{1+2+3}+frac{1}{1+2+3+4}+frac{1}{1+2+3+4+5}+...+frac{1}{1+2+3+4+...+59}chứng minh: N frac{2}{3}cho S frac{1}{1.2.3}+frac{1}{2.3.4}+...+frac{1}{37.38.39}chứng minh: S frac{1}{4}
Đọc tiếp
Cho I =\(\frac{1}{4^2}+\)\(\frac{1}{6^2}+\)\(\frac{1}{8^2}+...+\frac{1}{2006^2}\)chứng minh: I < \(\frac{334}{2007}\)Cho K = \(\frac{1}{5^2}+\frac{1}{9^2}+...+\frac{1}{409^2}\)chứng minh: K < \(\frac{1}{12}\)cho M = \(\frac{3}{4}+\frac{8}{9}+\frac{15}{16}+...+\frac{2499}{2500}\)chứng minh: M > 48cho N = \(\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+\frac{1}{1+2+3+4+5}+...+\frac{1}{1+2+3+4+...+59}\)chứng minh: N < \(\frac{2}{3}\)cho S = \(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{37.38.39}\)chứng minh: S <\(\frac{1}{4}\)
M=\(\frac{1}{1+2+3}\)+\(\frac{1}{1+2+3+4}\)+..............+\(\frac{1}{1+2+3+...+59}\)
chứng minh M<\(\frac{2}{3}\)
Chứng minh
M=\(\frac{1}{1+2+3}\)+\(\frac{1}{1+2+3+4}\)+\(\frac{1}{1+2+3+4+5}\)+.....+\(\frac{1}{1+2+3+....+59}\)<\(\frac{2}{3}\)
Cho M = \(\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+......+\frac{1}{1+2+3+.....+89}\)
Chứng minh M\(< \frac{2}{3}\)
\(Cho:M=\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+59}\)
Chứng mính: \(M<\frac{2}{3}\)
Cho \(M = (1+\frac{1}{2}+\frac{1}{3}+...++\frac{1}{2018}).2 .3 .4. ... .2018\)
Chứng minh : M chia hết cho 2019