Question

cho ham so y=f(x)=4x^2-5.a,tinh f(3).f(-1/2) b,tim x de f(x)=-1

 

Answer 1

\(a,\)

\(y=f\left(3\right)=4.3^2-5=31\)

\(y=f\left(-\frac{1}{2}\right)=4.\left(-\frac{1}{2}\right)^2-5=-4\)

\(b,\)

\(y=f\left(x\right)=4x^2-5\)

\(\Leftrightarrow4.x^2-5=-1\)

\(\Leftrightarrow4.x^2=4\)

\(\Leftrightarrow x^2=1\)

\(\Leftrightarrow x=1\)

Answer 2

 y=ƒ (3)=4.3²−5=31

y=ƒ (−1/2 )=4.(−1/2 )2−5=−4

b,

y=ƒ (x)=4x2−5

⇔4.x2−5=−1

⇔4.x²=4

⇔x²=1

⇔x=1

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