CHO HAM SO : y=x \(^2\) - 5x +6
a) tim cac gia tri cua x sao cho ve phai cua cong thuc co nghia
b) tinh y ; biet x= -\(\frac{1}{3}\) ; x= 0,5 ; x=0 ; x=1
c) tim x khi biet y = 0
Cho ham so y=f(x) xac dinh voi moi x E R thoa man tinh chat: f(a+b)= f(ab) voi moi a,b E R va f(-3). Tinh f(2014)
Please for kt Toan hoc ky 1
cho ham so f(x) xac dinh voi x thuoc R biet voi moi x ta luon co f(x) +3 x f(1/x) =x^2. tinh f(x)
cho ham so y=f(x) biet rang voi moi x ta deu co:f(x)-f(1/x)=x^2.tinh f(3)
giai ho minh nha
cho ham so f(x) xac dinh voi moi x
Biet vs moi gia tri tuong ung cua x, ta luon co :f(x)+2f(1/x)=x2.Tinh f(4)
neu ta co tinh chat x>y,y>z thi hay so sanh \(\frac{13}{38}va\frac{-12}{-37}\)
ve do thi ham so y=\(\frac{-1}{4}\)x voi x\(\in\eta\)
diem (-2;1/2 ) co thuoc do thi ham so khong
bai 1 :
biet do thi ham so y=\(\left(\sqrt{a}-3\right)x\) di qua \(N\left(\sqrt{5};\sqrt{5}\right)\)( a la hang so)
vay a=?
Bai 2:
Cho \(Q\left(x\right)=ax^2+bx+c\)thoa man :
\(Q\left(0\right)=1;Q\left(1\right)=6;Q\left(2\right)=5\)Tinh b
bai 3 :tinh gia tri bieu thuc
\(A=3x+2y+z\)biet \(\left(x-3y^2\right)+\left(y-1\right)^2+\left(x+z\right)^2=0\)
Bai 1:a)Tim x biet\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\times\left(x+1\right)}=\frac{2009}{2011}\)
b)\(\left(x-1\right)\times f\left(x\right)=\left(x+4\right)\times f\left(x\right)\)voi moi x
Bai 2;Tim x;y;z biet a)\(\frac{y+z+1}{x}=\frac{x+z+2}{y}=\frac{x+y-3}{z}\) b)\(\frac{2x+1}{5}=\frac{3y-z}{7}=\frac{2x+3y-1}{6x}\)