Question

cho hai đa thức :

M = \(x^2-2xy+y^2\)

N = \(y^2+2xy+x^2+1\)

a, Tính M + N 

b, tính M - N 

 

Answer 1

a, M + N = \(\left(x^2-2xy+y^2\right)+\left(y^2+2xy+x^2+1\right)\)

               =\(2x^2+2y^2+1\)

b,M - N =\(\left(x^2-2xy+y^2\right)-\left(y^2+2xy+x^2+1\right)\)

             =\(-4xy-1\)

Answer 2

\(M+N=\left(x^2-2xy+y^2\right)+\left(y^2+2xy+x^2+1\right)\)

\(\Rightarrow M+N=2x^2+2y^2+1\)

\(M-N=\left(x^2-2xy+y^2\right)-\left(y^2+2xy+x^2+1\right)\)

\(\Rightarrow M-N=-4xy-1\)

tíc mình nha

Answer 3

\(a.M+N=\left(x^2-2xy+y^2\right)+\left(y^2+2xy+x^2+1\right)\)

                 \(=x^2-2xy+y^2+y^2+2xy+x^2+1\)

                 \(=\left(x^2+x^2\right)+\left(-2xy+2xy\right)+\left(y^2+y^2\right)+1\)

                 \(=2x^2+2y^2+1\)

\(b.M-N=\left(x^2-2xy+y^2\right)-\left(y^2+2xy+x^2+1\right)\)

                 \(=x^2-2xy+y^2-y^2-2xy-x^2-1\)

                 \(=\left(x^2-x^2\right)+\left(-2xy-2xy\right)+\left(y^2-y^2\right)-1\)

                 \(=-4xy-1\)

T mk nhé bn ^...^ ^_^

Answer 4

a)  => M +N = \(x^2-2xy+y^2+y^2+2xy+x^2+1\)

                   \(=2x^2+2y^2+1\)

                     \(=2\left(x^2+y^2\right)+1\)

b)  => M-N = \(x^2-2xy+y^2-y^2-2xy-x^2-1\)

                 \(=\left(-4xy\right)-1\)

Answer 5

a) M + N = ( x^2 - 2xy + y^2 ) + ( y^2 + 2xy + x^2 + 1 )

              = ( x^2 + x^2 ) + ( y^2 + y^2 ) + ( - 2xy + 2xy ) + 1

              = 2x^2 + 2y^2 + 1

b) M - N  = ( x^2 - 2xy + y^2 ) - ( y^2 + 2xy + x^2 + 1 )

              = ( x^2 - x^2 ) + ( - 2xy - 2xy ) + ( y^2 - y^2 ) + 1

              = - 4xy + 1