Các câu hỏi tương tự
a, Đặt \(\frac{a}{b}=\frac{c}{d}=k\Rightarrow a=b.k,c=d.k\)
+) \(\frac{5a+3b}{5a-3b}=\frac{5.b.k+3.b}{5.b.k-3.b}=\frac{b.\left(5k+3\right)}{b.\left(5k-3\right)}=\frac{5k+3}{5k-3}\left(1\right)\)
+) \(\frac{5c+3d}{5c-3d}=\frac{5.d.k+3.d}{5.d.k-3.d}=\frac{d.\left(5k+3\right)}{d.\left(5k-3\right)}=\frac{5k+3}{5k-3}\left(2\right)\)
Từ (1) và(2) => ĐPCM
Cho \(\frac{a}{b}=\frac{b}{c}=\frac{c}{d}\)CMR \(\left(\frac{a+b+c}{b+c+d}\right)^3=\frac{a}{d}\)
Cho \(\frac{a}{b}=\frac{b}{c}=\frac{c}{d}\). Cmr: \(\left(\frac{a+b+c}{b+c+d}\right)^3=\frac{a}{d}\)
Cho: \(\frac{a}{b}\)=\(\frac{b}{c}\)=\(\frac{c}{d}\). C/m: \(\left(\frac{a+b+c}{b+c+d}\right)^3\)=\(\frac{a}{d}\)
1. Cho: frac{a}{b} frac{c}{d}. C/m : a) frac{10a-b}{3a+7b} frac{10c-d}{3c+7d}b) frac{7a^2+3ab}{11a^2-8b^2} frac{7c^2+3cd}{11c^2-8d^2}2. Cho : frac{a}{b}frac{b}{c}frac{c}{d}. C/m : left(frac{a+b+c}{b+c+d}right)^3 frac{a}{d}
Đọc tiếp
1. Cho: \(\frac{a}{b}\)= \(\frac{c}{d}\). C/m : a) \(\frac{10a-b}{3a+7b}\)= \(\frac{10c-d}{3c+7d}\)
b) \(\frac{7a^2+3ab}{11a^2-8b^2}\)= \(\frac{7c^2+3cd}{11c^2-8d^2}\)
2. Cho : \(\frac{a}{b}\)=\(\frac{b}{c}\)=\(\frac{c}{d}\). C/m : \(\left(\frac{a+b+c}{b+c+d}\right)^3\)= \(\frac{a}{d}\)
Cho \(\frac{a}{b}=\frac{b}{c}=\frac{c}{d}\).Chứng minh rằng:\(\left(\frac{a+b+c}{b+c+d}\right)^3\)=\(\frac{a}{d}\)
Tính giá trị biểu thức:a,Aleft(-1right).left(-1right)^2.left(-1^3right).left(-1right)^4...........left(-1right)^{2016}.left(-1right)^{2017}b,B70.left(frac{131313}{565656}+frac{131313}{727272}+frac{131313}{909090}right)c,Cfrac{2a}{3b}+frac{3b}{4c}+frac{4c}{5d}+frac{5d}{2a}biếtfrac{2a}{3b}frac{3b}{4c}frac{4c}{5d}frac{5d}{2a}
Đọc tiếp
Tính giá trị biểu thức:
\(a,A=\left(-1\right).\left(-1\right)^2.\left(-1^3\right).\left(-1\right)^4...........\left(-1\right)^{2016}.\left(-1\right)^{2017}\)
\(b,B=70.\left(\frac{131313}{565656}+\frac{131313}{727272}+\frac{131313}{909090}\right)\)
\(c,C=\frac{2a}{3b}+\frac{3b}{4c}+\frac{4c}{5d}+\frac{5d}{2a}\)
biết\(\frac{2a}{3b}=\frac{3b}{4c}=\frac{4c}{5d}=\frac{5d}{2a}\)
\(Cho:\frac{a}{b}=\frac{b}{c}=\frac{c}{d}=\frac{d}{a}\) biết \(a=b=c=d\). Tính tổng \(M=\frac{2a-b}{c+d}+\frac{2b-c}{a+d}+\frac{2c-d}{a+d}+\frac{2d-a}{b+c}\)
1 tháng 1 2018 lúc 15:21
cho : \(\frac{a}{b}=\frac{c}{d}\) \(\left(a;b;c\ne0;a\ne b,b\ne c;c\ne d\right)\)
c\m : \(\frac{a}{a-b}=\frac{c}{c-d}\)