Cho \(\frac{a}{b}=\frac{c}{d}\) chứng minh
a) \(\frac{a.b}{c.d}=\left(\frac{a-b}{c-d}\right)^2\)
b) \(\left(\frac{a+b}{c+d}\right)^3=\frac{a^3-b^3}{c^3-d^3}\)
c) \(\frac{5a+3b}{5c+3d}=\frac{5a-3b}{5c-3d}\)
Cho tỉ lệ thức:\(\frac{a}{b}=\frac{c}{d}\left(a;b;c;d\ne0\right)\)
Chứng minh:
a) \(\frac{a+b}{b}=\frac{c+d}{d}\)
b) \(\frac{5a+3b}{5a-3b}=\frac{5c+3d}{5c-3d}\)
từ \(\frac{a}{b}\)=\(\frac{c}{d}\)chứng minh rằng;
\(\frac{a}{a-b}\)=\(\frac{c}{c-d}\)\(\frac{a+b}{b}=\frac{c+d}{d}\)\(\frac{5a+3b}{5a-3b}=\frac{5c=3d}{5c-3d}\)\(\frac{^{b^2}}{d^2}=\frac{\left(a+b\right)^2}{\left(c+d\right)^2}\)cho \(\frac{a}{b}=\frac{c}{d}\left(c\ne+-\frac{3}{5}d\right)\)
chứng minh \(\frac{5a+3b}{5c+3d}=\frac{5a-3b}{5c-3d}\)
Chứng minh rằng: Nếu \(\frac{a}{c}=\frac{b}{d}\)thì \(\frac{5a+3b}{5a-3b}=\frac{5c+3d}{5c-3d}\)
Chứng minh rằng nếu
\(\frac{a}{b}=\frac{c}{d}\)thì \(\frac{5a+3b}{5a-3b}=\frac{5c+3d}{5c-3d}\)
Cho \(\frac{a}{b}=\frac{c}{d}\)chứng minh:
\(\frac{a}{a-b}=\frac{c}{c-d}\)\(\frac{5a+3d}{5a-3b}=\frac{5c+3d}{5c-3d}\)\(\frac{ab}{cd}=\frac{\left(a-b\right)^2}{\left(c-d\right)^2}\)
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Cho \(\frac{a}{b}=\frac{c}{d}\)chứng minh rằng:
a, \(\frac{a-b}{a+b}=\frac{c-d}{c+d}\)
b, \(\frac{5a+3b}{5a-3b}=\frac{5c+3d}{5c-3d}\)
c, \(\frac{7a^2+3ab}{11a^2-8b^2}=\frac{7c^2+3cd}{11c^2-8d^2}\)
chứng minh rằng \(\frac{a}{b}=\frac{c}{d}\)thì
\(\frac{5a+3b}{5a-3b}=\frac{5c+3d}{5c-3d}\)