Question

Cho \(\frac{a}{a'}=\frac{b}{b'}=\frac{c}{c'}=4;\); a'+b'+c' khác 0;a'-3b'2c' khác 0.

Tính:\(\frac{a-3b+2c}{a'-3b'+2c'}\)

 

Answer 1

\(\frac{a}{a'}=\frac{b}{b'}=\frac{c}{c'}=\frac{3b}{3b'}=\frac{2c}{2c'}=\frac{a-3b+2c}{a'-3b'+2c'}\) mà\(\frac{a}{a'}=4\Rightarrow\frac{a-3b+2c}{a'-3b'+2c'}\)

Answer 2

thank you!