\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\) => (a + 5)(b - 6) = (a - 5)(b + 6) => ab - 6a + 5b - 30 = ab + 6a - 5b - 30
=>\(-6a+5b\) = 6a - 5b =\(-\left(6a-5b\right)\) => 6a - 5b = 0 => 6a = 5b => \(\frac{a}{b}=\frac{5}{6}\)(đpcm)
\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\Rightarrow\frac{a+5}{b+6}=\frac{a-5}{b-6}=\frac{2a}{2b}=\frac{a}{b}\)
Suy ra:\(\frac{a+5}{b+6}=\frac{a}{b}\Rightarrow a.\left(b+6\right)=b.\left(a+5\right)\)
=>ab+6a=ab+5b
=>6a=5b
=>\(\frac{a}{b}=\frac{5}{6}\)
Phan Thanh Tịnh lớp 7 có lẽ ko có khả năng làm như vậy