\(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}=\frac{12x-8y}{16}=\)\(\frac{6z-12x}{9}=\frac{8y-6z}{4}\)\(=\frac{12x-8y+6z-12x+8y-6z}{16+9+4}=\frac{0}{29}=0\)
\(\Rightarrow3x-2y=0\Rightarrow\frac{x}{2}=\frac{y}{3}\left(1\right)\)
\(\Rightarrow2z-4x=0\Rightarrow\frac{z}{4}=\frac{x}{2}\left(2\right)\)
Từ (1) và (2) => \(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
~~ học tốt ~~