(3x-2y)/4 = (2z-4x)/3 = (4y-3z)/2 =(12x-8y)/16 = (6z-12x)/9 = (8y-6z)/4
Áp dụng t/c của dãy tỉ số = nhau, ta có:
(12x-8y)/16 = (6z-12x)/9 = (8y-6z)/4 = (12x-8y + 6z-12x + 8y-6z)/(16+9+4) = 0
<=>
{12x - 8y = 0
{6z - 12x = 0
{8y - 6z = 0
<=>
{x/2 = y/3
{z/4 = x/2
{y/3 = z/4
<=> x/2 = y/3 = z/4
Cho \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}.\)Chứng minh rằng \(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
Cho \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}\) . Chứng minh rằng : \(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
Cho \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}\)
Chứng minh rằng \(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
Cho \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}\) Chứng minh rằng \(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
Cho \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}\)
Chứng minh rằng:\(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
Chứng minh rằng : x/2 = y/3 = z/4
BIết :\(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}\)
Cho \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}\)Chứng minh rằng \(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
cho \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}\).chứng minh \(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
Cho \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}\)
Chứng minh rằng \(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
