Question

Cho đa thức A(x) = m + nx + px (x - 1) , biết A(0) = 5; A(1) = -2; A(2) = 7. Tìm đa thức A(x)

Answer 1

\(A\left(0\right)=m=5\)

\(A\left(1\right)=m+n=-2\Rightarrow n=-2-5=-7\)

\(A\left(2\right)=m+2n+2p=5-14+2p=7\Rightarrow2p=16\Rightarrow p=8\)

\(\Rightarrow A\left(x\right)=5-7x+56x==49x +5\)

Answer 2

A(x)=m+nx+px(x-1)

=>A(0)=m+n*0+p*0*-1=5 hay A(0)=m=5

A(1)=5+n*1+p*1*0=5+n=-2 =>n=-7

A(2)=5+(-7)*2+p*2*1=7 =>p=6

vậy A(x)=5-7x+6x(x-1)

Answer 3

t i c k cho mk

Answer 4

@ Kun@ A(x)=5+7x+8x(x-1)

Answer 5

sai r kirito kun

px(x-1)=px^2-px=8*x^2-8x mà

Answer 6

mk viết sai p=8 nha