Cho n! = 1.2.3.....n. Chứng minh A = 1/2! + 2/3! +...+2013/2014! < 1
Biết: n!= 1.2.3.....n (n\(\in\)N* ; n \(\ge\)2)
A = \(\dfrac{1}{2!}+\dfrac{2}{3!}+...+\dfrac{2013}{2014!}\)< 1
Biết:n!=1.2.3....n
Chứng tỏ rằng :A=1/2!+2/3!+...+2013/2014!<1
Mình sẽ tick cho
Cho A = \(1.2.3...2013.2014\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2013}+\frac{1}{2014}\right)\). Chứng minh rằng A chia hết cho 2015
Cho C = 1*2*3*.....*2014*(1+1/2+1/3+1/4+.....1/2014) chứng minh C là 1 số tự nhiên chia hết cho 2^2014
Bài 6: So sánh
a,\(\dfrac{1}{2}\)+\(\dfrac{1}{_{ }2^2}\)+\(\dfrac{1}{2_{ }^3}\)+...+\(\dfrac{1}{2^{2014}}\)và 1 b,\(\dfrac{10^{2018}+5}{10^{2018}-8}\)và \(\dfrac{10^{2019}+5}{10^{2019}-8}\)
c,\(\dfrac{1}{1.2.3}\)+\(\dfrac{1}{2.3.4}\)+\(\dfrac{1}{3.4.5}\)+...+\(\dfrac{1}{23.24.25}\)và\(\dfrac{1}{4}\)
Cau 1: Tim n biet : 5/8 + 5/24 + 5/48 + 5/80 + ... + 5/2n + 2 . 2n + 4 = 189/112
Cau 2 : Cho A = 1 + 1/1.2 + 1/1.2.3 + ... + 1/1.2.3...2014. So sanh A voi 2
Cau 3 : Tim n biet : 5/3 + 5/15 + 5/35 + 5/63 +...+ 5/2n + 1 . 2n + 3 = 172/69
Biết n!=1.2.3....n
CMR A=\(\frac{1}{2!}+\frac{2}{3!}+....+\frac{2013}{2014!}< 1\)
a) 22344.36 + 44688.82
1.2.3. ... .2015 1.2.3. ... .2014 1.2.3. ... .20 − − 13.20142
b) 52x - 3 – 2.52 = 52 .3
x + ( x+ 1) ( x + 2) ... ( x + 30) = 1240