Cho C= xmu 10- xmu 5+ x mu 2 - x mu 1 =1 tim x de C=0
tim cac gia tri cua x de bieu thuc sau nhan gia tri am
a)x mu 2 + 5x b)x mu 2 - 5/2x c)3(2x+3)(3x-5) d)x - 2/x-6 e) x mu 2 -1/x mu 2
tim cac gia tri cua x de bieu thuc sau nhan gia tri duong
a) x mu 2 + 4x b)2x mu 2 - 4x c)(x-3)(x+7) d)5(3x +1 )(4x-3) e)(1/2-x)(1/3-x)
[1/2x mu 2(2x-1) mu m-1/2 x mu(m +2]:1/2x mu 2 =0
tim x
a) \3x=9\=\4-x\+0
b)(x-5)16 =(x-5)12
c)(2x-5)(5-x mu 2)(x mu 2 +1=0
d)5 mu x + 5 mu x+2 =650
Minh can gap giup minh voi:
a) \3x=9\=\4-x\+0
b)(x-5)16 =(x-5)12
c)(2x-5)(5-x mu 2)(x mu 2 +1=0
d)5 mu x + 5 mu x+2 =650
Tim x,y la so nguyen
a) 2x-3y+5= xy
b) x mu 2 +2xy+2x+4y
B2 Tim x,y la so nguyen to
x mu 2 -2y mu 2 =1
B3 Tim so tu nhienx,y
7 .(x-2004) mu 2 = 23- y mu 2
1) (3x-5/9) mu 200 + (3y+0,4/3) mu 2008 =0
tim cap x;y thoa man
2) (2x-1) mu 2k + (y-(1/3))mu 4k = 0
ai truoc thi mk like
cho c =x^10-x^5+x^2-x+1 tim x de c =0