\(\left(-m+n-p\right)-\left(-m-n-p\right)\)
\(=-m+n-p+m+n+p\)
\(=\left(-m+m\right)+\left(-p+p\right)+\left(n+n\right)\)
\(=2n\)
Vậy \(\left(-m+n-p\right)-\left(-m-n-p\right)=2n\)
\(\left(-m+n-p\right)-\left(-m-n-p\right)\)
\(=-m+n-p+m+n+p\)
\(=\left(-m+m\right)+\left(-p-p\right)+\left(n+n\right)\)
\(=0+0+\left(n+n\right)\)
\(=0+\left(n+n\right)\)
\(=n+n\)
\(=2n\)
Vậy biểu thức (-m+n-p)-(-m-n-p) =2n