Ta có : 50 x 49 + 53 x 50 = 50 x ( 49 + 53 ) = 50 x 102
Vì 50 x 102 > 101 x 50
Nên B > A
Hay A < B
Ta có :
\(A=101\times50\)
\(B=50\times49+53\times50\)
\(B=50\times\left(49+53\right)\)
\(B=50\times102\)
Vì \(101< 102\Rightarrow A< B\)
A = 101 x 50
B = 50 x 49 + 53 x 50
B = (49 + 53) x 50
B = 102 x 50
Vì 101 < 102.Vậy 101 x 50 < 50 x 49 + 53 x 50.
A = 101 x 50
B = 50 x 49 + 53 x 50
B = 50 x ( 49 + 53 )
B = 50 x 102
Vì 101 < 102 nên A < B
ta có
A = 101 . 50
B = 50 . 49 + 53 . 50
B = 50 . ( 49 + 53 )
B = 50 . 102
vì 101 < 102 => A < B
