\(B=\frac{1+\left(1+2\right)+\left(1+2+3\right)+...+\left(1+2+3+...+98\right)}{1.98+2.97+3.96+...+98.1}\)
\(B=\frac{1+1+2+1+2+3+...+1+2+3+...+98}{1.98+2.97+3.96+...+98.1}\)
\(B=\frac{1.98+2.97+3.96+...+98.1}{1.98+2.97+3.96+...+98.1}\)
\(B=1\)
Cho B=\(\frac{1+\left(1+2\right)+\left(1+2+3\right)+...+\left(1+2+3+...+98\right)}{1.98+2.97+3.96+...+98.1}\) Rút gọn B ta được B=
Cho B =\(\frac{1+\left(1+2\right)+\left(1+2+3\right)+...+\left(1+2+3+...+98\right)}{1.98+2.97+3.96+...+98.1}\)
Rút gọn B ta được B =
Cho B = \(\frac{1+\left(1+2\right)+\left(1+2+3\right)+...+\left(1+2+3+...+98\right)}{1.98+2.97+3.96+4.95+...+98.1}\)
Rút gọn B . Ta được B = ?
Cho B=\(\frac{1+\left(1+2\right)+\left(1+2+3\right)+...+\left(1+2+3+...+98\right)}{1.98+2.97+3.96+...+98.1}\)
Rút gọn B ta được B=
giải giùm minh nha mai thi violympic rồi cảm ơn nha
Cho \(B=\frac{1+\left(1+2\right)+\left(1+2+3\right)+...+\left(1+2+3+...+98\right)}{1.98+2.97+3.96+...+98.1}\)
Rút gọn B.
TÍNH NHANH RÚT GỌN:\(\frac{1+\left(1+2\right)+\left(1+2+3\right)+....+\left(1+2+3+....+98\right)}{1.98+2.97+3.96+....+98.1}\)
A = \(\frac{1+\left(1+2\right)+\left(1+2+3\right)+.....+\left(1+2+3+...+\left(98\right)\right)}{1.98+2.97+3.96+...+98.1}\)
1 , Tinh A = \(\frac{1+\left(1+2\right)+\left(1+2+3\right)+...+\left(1+2+3+.....+98\right)}{1.98+2.97+3.96+.....+98.1}\)
Tính tổng:
\(D=\frac{1+\left(1+2\right)+\left(1+2+3\right)+...+\left(1+2+...+98\right)}{1.98+2.97+3.96+...+98.1}\)
