A= -(3/4 . 8/9 . 15/16 ... 9999/10000)
=-( (3.8.15....9999)/(4.9.16...10000))
= - (( 1.3.2.4.3.5...99.101)/(2.2.3.3.4.4...100.100))
= -( ( 1.2.3.4...99).(3.4.5..101) / (2.3.4...100) . (2.3.4..100))
= -101/200< -100/200 = -1/2
Vậy A < -1/2
A= -(3/4 . 8/9 . 15/16 ... 9999/10000)
=-( (3.8.15....9999)/(4.9.16...10000))
= - (( 1.3.2.4.3.5...99.101)/(2.2.3.3.4.4...100.100))
= -( ( 1.2.3.4...99).(3.4.5..101) / (2.3.4...100) . (2.3.4..100))
= -101/200< -100/200 = -1/2
Vậy A < -1/2
Cho: \(A=\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right)...\left(\frac{1}{100^2}-1\right)\)
So sánh A với \(\frac{-1}{2}\)
Cho \(A=\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right)...\left(\frac{1}{100^2}-1\right)\)
So sánh A với \(-\frac{1}{2}\)
Cho A=\(\left(\hept{\begin{cases}1\\2^2\end{cases}}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right)....\left(\frac{1}{100^2}-1\right)\)So sánh A với \(-\frac{1}{2}\)
1. tính A= \(\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}...\frac{899}{30^2}\)
2. tính B= \(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}...\frac{30}{62}.\frac{31}{64}\)
3. So sánh C= \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{20}\right)\)với \(\frac{1}{21}\)
4. So sánh D= \(\left(1-\frac{1}{4}\right).\left(1-\frac{1}{9}\right).\left(1-\frac{1}{16}\right)...\left(1-\frac{1}{100}\right)\)với \(\frac{11}{19}\)
Cho \(A=\left(\frac{1}{2^2}-1\right)\times\left(\frac{1}{3^2}-1\right)\times\left(\frac{1}{4^2}-1\right)\times...\times\left(\frac{1}{100^2}-1\right)\)
So sánh A với \(-\frac{1}{2}\)
cho A=\(\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right)....\left(\frac{1}{100^2}-1\right)\)
so sánh A với \(\frac{-1}{2}\)
A = \(\left[\frac{1}{2^2}-1\right].\left[\frac{1}{3^2}-1\right].\left[\frac{1}{4^2}-1\right].....\left[\frac{1}{100^2}-1\right]\)\(\)
so sánh A với \(\frac{-1}{2}\)
So sánh \(A=\left(\frac{1}{2^2}-1\right)\left(\frac{1}{3^2}-1\right)\left(\frac{1}{4^2}-1\right).....\left(\frac{1}{100^2}-1\right)\) VÀ \(-\frac{1}{2}\)
Cho \(A=\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right)...\left(\frac{1}{100^2}-1\right)\)
So sánh A với \(\frac{-1}{2}\)
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