Question

cho \(A=\frac{196}{197}+\frac{197}{198}\)và \(B=\frac{196+197}{197+198}\)

Answer 1

Ta có :

\(B=\frac{196+197}{197+198}=\frac{196}{197+198}+\frac{197}{197+198}\)

Vì : 

\(\frac{196}{197}>\frac{196}{197+198};\frac{197}{198}>\frac{197}{197+198}\)

=> A > B
=))

Answer 2

ta có:

\(B=\frac{196+197}{197+198}=\frac{196}{197+198}+\frac{197}{197+198}\)

Mà: \(\frac{196}{197+198}< \frac{196}{197}\)

   \(\frac{197}{197+198}< \frac{197}{198}\)

=> \(\frac{196}{197}+\frac{197}{198}>\frac{196+197}{197+198}\)

Vậy:\(A>B\)

Answer 3

A=\(\frac{77617}{39006}\)  ;       B=\(\frac{393}{395}\)

A>1                                       B<1

     Vậy A>B

Answer 4

Ta có :

B=\(\frac{196+197}{197+198}=\frac{196}{197+198}+\frac{197}{197+198}\)

Vì \(\frac{196}{197}>\frac{196}{197+198}\) và  \(\frac{197}{198}>\frac{197}{197+198}\) 

Vậy A>B