Vì \(\frac{a}{b}< \frac{c}{d}\Rightarrow ad< bc\)
Quy đồng mẫu hai phân số \(\frac{2019a+c}{2019b+d}\) và \(\frac{c}{d}\)
\(\frac{2019a+c}{2019b+d}=\frac{d\left(2019a+c\right)}{d\left(2019b+d\right)}=\frac{2019ad+cd}{2019bd+d^2}\)
\(\frac{c}{d}=\frac{c\left(2019b+d\right)}{d\left(2019b+d\right)}=\frac{2019bc+2019cd}{2019bd+d^2}\)
Vì ad < bc nên 2019ad + cd < 2019bc + 2019cd => \(\frac{2019a+c}{2019b+d}< \frac{c}{d}\)(đpcm)