Question

cho a,b,c>0/ CMR

\(\frac{-a+b+c}{2a}+\frac{a-b+c}{2b}+\frac{a+b-c}{2c}>=\frac{3}{2}\)

( là lớn hơn hoặc bằng nha )

Answer 1

<=> \(\frac{b+c-a}{2a}+1+\frac{a-b+c}{2b}+1+\frac{a+b-c}{2c}+1\ge\frac{3}{2}+3\)

<=> \(\frac{a+b+c}{2c}+\frac{a+b+c}{2b}+\frac{a+b+c}{2c}\ge\frac{9}{2}\)

<=> \(\left(a+b+c\right)\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)\ge9\)

<=> \(\frac{a}{a}+\frac{a}{b}+\frac{a}{c}+\frac{b}{a}+\frac{b}{b}+\frac{b}{c}+\frac{c}{a}+\frac{c}{b}+\frac{c}{c}\ge9\)

<=> \(\left(\frac{a}{b}+\frac{b}{a}\right)+\left(\frac{a}{c}+\frac{c}{a}\right)+\left(\frac{b}{c}+\frac{c}{b}\right)\ge6\)

Ap dung bdt  \(\frac{a}{b}+\frac{b}{a}\ge2\)

Suy ra ve trai >= 2.3=6=ve phai

=> DPCM

Dau = xay ra <=> a=b=c

mik phai di hoc nen tra loi tat mong ban thong cam

Answer 2

cảm ơn nhiều ạ