Các câu hỏi tương tự
(1) (a+b+c)2a2+b2+c2+2ab+2bc+2ac(a+b+c)2a2+b2+c2+2ab+2bc+2ac(2) (a+b−c)2a2+b2+c2+2ab−2bc−2ac(a+b−c)2a2+b2+c2+2ab−2bc−2ac(3) (a−b−c)2a2+b2+c2−2ab−2ac+2bc(a−b−c)2a2+b2+c2−2ab−2ac+2bc(4) a3+b3(a+b)3−3ab(a+b)a3+b3(a+b)3−3ab(a+b)(5) a3−b3(a−b)3+3ab(a−b)a3−b3(a−b)3+3ab(a−b)(6) (a+b+c)3a3+b3+c3+3(a+b)(b+c)(c+a)(a+b+c)3a3+b3+c3+3(a+b)(b+c)(c+a)(7) a3+b3+c3−3abc(a+b+c)(a2+b2+c2−ab−bc−ac)a3+b3+c3−3abc(a+b+c)(a2+b2+c2−ab−bc−ac) (8) (a−b)3+(b−c)3+(c−a)33(a−b)(b−c)(c−a)(a−b)3+(b−c)3+(c−a)33(a−b)(b−c)(c−a)(9)...
Đọc tiếp
(1) (a+b+c)2=a2+b2+c2+2ab+2bc+2ac(a+b+c)2=a2+b2+c2+2ab+2bc+2ac
(2) (a+b−c)2=a2+b2+c2+2ab−2bc−2ac(a+b−c)2=a2+b2+c2+2ab−2bc−2ac
(3) (a−b−c)2=a2+b2+c2−2ab−2ac+2bc(a−b−c)2=a2+b2+c2−2ab−2ac+2bc
(4) a3+b3=(a+b)3−3ab(a+b)a3+b3=(a+b)3−3ab(a+b)
(5) a3−b3=(a−b)3+3ab(a−b)a3−b3=(a−b)3+3ab(a−b)
(6) (a+b+c)3=a3+b3+c3+3(a+b)(b+c)(c+a)(a+b+c)3=a3+b3+c3+3(a+b)(b+c)(c+a)
(7) a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ac)a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ac)
(8) (a−b)3+(b−c)3+(c−a)3=3(a−b)(b−c)(c−a)(a−b)3+(b−c)3+(c−a)3=3(a−b)(b−c)(c−a)
(9) (a+b)(b+c)(c+a)−8abc=a(b−c)2+b(c−a)2+c(a−b)2(a+b)(b+c)(c+a)−8abc=a(b−c)2+b(c−a)2+c(a−b)2
(10) (a+b)(b+c)(c+a)=(a+b+c)(ab+bc+ca)−abc(a+b)(b+c)(c+a)=(a+b+c)(ab+bc+ca)−abc
(11) ab2+bc2+ca2−a2b−b2c−c2a=(a−b)3+(b−c)3+(c−a)33ab2+bc2+ca2−a2b−b2c−c2a=(a−b)3+(b−c)3+(c−a)33
(12)ab3+bc3+ca3−a3b−b3c−c3a=(a+b+c)[(a−b)3+(b−c)3+(c−a)3]3ab3+bc3+ca3−a3b−b3c−c3a=(a+b+c)[(a−b)3+(b−c)3+(c−a)3]3
Chứng minh giùm mik hằng đẳng thức kia vs
a3 + b3 + c3 = 3abc và abc ≠ 0. Tính P = ab2/(a2 + b2 – c2) + bc2/(b2 + c2 – a2) + ca2/(c2 + a2 – b2)
Chứng minh:a)
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Đọc tiếp
Chứng minh:
a) ( a 2 - ab + b 2 ) ( a + b ) = a 3 + b 3 ;
b) ( a 3 + a 2 b + ab 2 + b 3 ) ( a - b ) = a 4 - b 4 ;
Cho a, b, c la do dai ba canh cua mot tam giac . Chung minh rang :
\(\frac{1}{a+b-c}+\frac{1}{a+c-b}+\frac{1}{b+c-a}\ge\frac{1}{a+b+c}\)
chung minh rang a,b,c la do dai 3 canh cua mot tam giac thi m=4a2b2-(a2+b2-c2)2 luon duong
Cho bieu thuc ( b2 + c2 - a2 ) 2 - b2c2
a) Phan tich bieu thuc A thanh nhan tu
b) Chung minh rang : neu a,b,c la do dai 3 canh cua mot tam giac thi A<0
Cho tam giac ABC deu co canh dai 12cm, goi M la trung diem cua BC, lay diem D tren canh AB, diem E tren canh AC sao cho AD = 3cm, AE = 8cm
a) chung minh tam giac MBD dong dang voi tam giac ECM
b) tinh goc DME va ty so ME/MD
c) chung minh tam giac MBD dong dang voi tam giac EMD
d) chung minh DM la tia phan giac cua goc BDE
Cho tam giac ABC duong cao AD,H la truc tam cua tam giac .Lay M bat ki thuoc canh BC .Goi F,E la hinh chieu cua M tren AB,AC Goi I la trung diem cua AM
a,Xac dinh dang cua tu giac
b,chung minh rang cac duong thang MH,ID,EF dong quy
Cho tam giac ABC vuong tai A (AB<AC), duong cao AH. Tren canh AC lay diem E sao cho AE=AB. Goi M la trung diem cua BE. Chung minh rang HM la tia phan giac cua goc AHC