\(\frac{a+b-c}{c}+2=\frac{b+c-a}{a}+2=\frac{c+a-b}{b}+2\)
\(\frac{a+b+c}{c}=\frac{b+c+a}{a}=\frac{c+a+b}{b}\)
=>a=b=c
=>A=(1+b/a)(1+a/c)(1+c/b) = (1+1)(1+1)(1+1) =2.2.2 =8
\(\frac{a+b-c}{c}+2=\frac{b+c-a}{a}+2=\frac{c+a-b}{b}+2\)
\(\frac{a+b+c}{c}=\frac{b+c+a}{a}=\frac{c+a+b}{b}\)
=>a=b=c
=>A=(1+b/a)(1+a/c)(1+c/b) = (1+1)(1+1)(1+1) =2.2.2 =8
cho a,b,c la 3 so thuc duong thoa man dieu kien (a+b-c)/c=(b+c-a)/a=(c+a-b)/b tinh gia tri bieu thuc B=(1+b/a)*(1+a/c)*(1+c/b)
Cho a,b,c la ba so thuc duong thoa man (a^2).(b+c)=(b^2).(a+c)=20172018.tinh (c^2).(a+b)
cho a,b,c la 3 so thuc doi mot khac nhau va khac khong, thoa man: a+1/b=b+1/c=c+1/a. hay chung minh rang abc=1 hoac abc=-1
cho cac so thuc a, b,c khac 0 thoa man a^2*(a+b)=b^2*(b+c)=2016. tinh bieu thuc A=c^2*(a+c)
cho 3 so duong thoa man a/(b+c)=b/(a+c)=c/(a+b)
tinh gia tri bieu thuc P=(b+c)/a+(a+c)/b+(a+b)/c
Cho a.b,c la 3 so khac 0 thoa man : ab + a + b / a + b = bc + b + c / b + c = ca + c + a/ c + a ( voi gia thiet cac ti so deu co nghia)
Tinh gia tri bieu thuc M = ab+bc+ca+2017/ a^2 + b^2 + c^2 + 2017
cho x,y,z la cac so nguyen duong va x+y+z la so le, cac so thuc a,b,c thoa man (a-b)/x=(b-c)/y=(a-c)/z. chung minh rang a=b=c
cho 3 so a,b,c khac 0 va thoa man a+b-c/c=a+c-b/b=b+c-a/a
tinh gia tri bieu thuc P=(a+b)(b+c)(c+a)=abc
cac ban giai giup minh bai tap nay khan cap nhe:
cho cac so a,b,c la ba so nguyen khac 0, thoa man: ab/(a+b)=bc/(b+c)=ac/(a+c) ( gia thiet cac ti le thuc deu co nghia). tinh M= (ab + bc + ca)/(a^2+b^2+c^2)
xin cam on rat nhieu