a:b=2,6
\(\Rightarrow\frac{a}{b}=\frac{26}{10}\Leftrightarrow\frac{a}{b}=\frac{13}{5}\)
=>\(\frac{a}{13}=\frac{b}{5}\)
áp dụng t/c dãy t/s = nhau
=> \(\frac{a}{13}=\frac{b}{5}=\frac{a+b}{18}\)
=> \(\frac{18}{13}=\frac{a+b}{a}\)
=> \(\frac{18}{5}=\frac{a+b}{b}\)
=> \(\frac{a+b}{b}-\frac{a+b}{a}=\frac{18}{5}-\frac{18}{13}\)
\(\Rightarrow\frac{a\left(a+b\right)}{ab}-\frac{b\left(a+b\right)}{ab}=\frac{144}{65}\)
\(\Rightarrow\frac{\left(a+b\right)\left(a-b\right)}{ab}=\frac{144}{65}\)
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