\(\sqrt{\left(1+a\right)\left(1+b\right)}\ge1+\sqrt{ab}\)
\(\Leftrightarrow\left(1+a\right)\left(1+b\right)\ge\left(\sqrt{ab}+1\right)^2\)
\(\Leftrightarrow ab+a+b+1\ge ab+2\sqrt{ab}+1\)
\(\Leftrightarrow a+b-2\sqrt{ab}\ge0\)
\(\Leftrightarrow\left(\sqrt{a}-\sqrt{b}\right)^2\ge0\)
Dấu "=" xảy ra \(\Leftrightarrow a=b>0\)