ab - ac + bc - c2 = -1
=> a.(b - c) + c.(b - c) = -1
=> (b - c) . (a + c) = -1
=> (b - c) . (a + c) = -1.1 = 1.(-1)
+) b - c = -1 thì a + c = 1
=> b - c + a + c = a + b = -1 + 1 = 0
+) b - c = 1 thì a + c = -1
=> b - c + a + c = a + b = 1 + (-1) = 0
Vậy a + b = 0.