Question

Cho A=4+2^2+2^3+2^4+...+2^2014. Chứng minh rằng A chia hết cho 1024

Answer 1

2A = 2^3 + 2^3 + 2^4 + ..... + 2^2015

2A - A = (2^3 - 2^3) + (2^4 - 2^4)+.......... + 2^2015 + (2^3 - 2^2 - 4)

A = 2^2015

Ta có: 1024 = 2^10

Vì 2^2015 chia hết cho 2^10 

Vậy A chia hết cho 1024         

Answer 2

Xin loi nha ko giup dc ban roi

Answer 3

2A=2^3-2^3+2^4+...+2^2015

2A-A=(2^3-2^3)+(2^4-2^4)+...2^2015

2A-A=0+0+ 2^2015

A=2^2015

Vay :1024=2^10

Vi 2^215:2^10

A:1024