Question

cho A=3n+2/4n+3 cm A la phan so toi gian

Answer 1

\(Ta\)\(có\): \(A=\frac{3n+2}{4n+3}\)

Đặt UCLN \(\left(3n+2;4n+3\right)=d\)

\(\Rightarrow\hept{\begin{cases}3n+2⋮d\\4n+3⋮d\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}12n+8⋮d\\12n+9⋮d\end{cases}}\)

\(\Rightarrow1⋮d\)

\(\Rightarrow d=1\)

Vậy A tối giảm

Answer 2

\(A=\frac{3n+2}{4n+3}\)

Gọi ƯCLN ( 3n+2;4n+3 ) là : d

\(\Rightarrow\hept{\begin{cases}3n+2⋮d\\4n+3⋮d\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}4.\left(3n+2\right)⋮d\\3.\left(4n+3\right)⋮d\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}12n+8⋮d\\12n+9⋮d\end{cases}}\)

\(\Rightarrow\left(12n+9\right)-\left(12n+8\right)⋮d\)

\(\Rightarrow1⋮d\)

\(\Rightarrow d=1\)

\(\Rightarrow\)ƯCLN ( 3n+2;4n+3) = 1

Vậy : A là phân số tối giản