ta có: a3 + b3 + c3 = 3abc
=> a3 + b3 + c3 - 3abc = (a+b+c).(a2 + b2 + c2 - ab - bc -ac) = 0
mà a + b + c khác 0
=> a2 + b2 + c2 - ab - bc - ac = 0
=> a = b = c
\(\Rightarrow A=\frac{a^2+b^2+c^2}{\left(a+b+c\right)^2}=\frac{a^2+a^2+a^2}{\left(a+a+a\right)^2}=\frac{3a^2}{\left(3a\right)^2}=\frac{3a^2}{3^2.a^2}=\frac{1}{3}.\)