cách kiếm GP cực nhanh như thế nào
A= \((2^3\times2^{36}\times3^{20}+2^{19}\times2^{20}\times3^{20})\div(2^{20}\times5^{40}\div5^{40})\)
\(\Rightarrow A=(2^{39}\times3^{20}+2^{39}\times3^{20})\div2^{20}\)
\(\Rightarrow A=2^{39}\times3^{20}(1+1)\div2^{20}\)
\(\Rightarrow A=2^{40}\times3^{20}\div2^{20}\)
\(\Rightarrow A=2^{20}\times3^{20}=6^{20}\)
Vậy: \(A=6^{20}\)