\(a+b+c=244abc\Rightarrow2\left(\frac{1}{ab}+\frac{1}{bc}+\frac{1}{ca}\right)=244.2\)
Tính theo công thức
\(\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)^2=\frac{1}{a^2}+\frac{1}{b^2}+\frac{1}{c^2}+2\left(\frac{1}{ab}+\frac{1}{bc}+\frac{1}{ca}\right)\)