Cho a,b,c>0 và abc=1. CMR:
\(\frac{1}{a^3\left(b+c\right)}+\frac{1}{b^3\left(c+a\right)}+\frac{1}{c^3\left(a+b\right)}\ge\frac{3}{2}\)
Cho \(a^3+b^3+c^3=3abc\)và \(abc\ne0;a+b+c=0\)
CMR \(\left(\frac{1}{a}+\frac{1}{b}\right)\left(\frac{1}{b}+\frac{1}{c}\right)\left(\frac{1}{c}+\frac{1}{a}\right)=0\)
Cho a,b,c > 0, abc=1
CMR:
\(\frac{a^3}{\left(1+b\right)\left(1+c\right)}=\frac{b^3}{\left(1+c\right)\left(1+a\right)}=\frac{c^3}{\left(1+b\right)\left(1+a\right)}\)>=\(\frac{3}{4}\)
a,Cho \(a,b,c\in\left[0;1\right].CMR:\)
\(\frac{1}{a+3b}+\frac{1}{b+3c}+\frac{1}{c+3a}\ge\frac{3}{3+abc}\)
b,Cho a,b,c>0 thỏa mãn:abc=1
\(CMR:\frac{1}{a^3\left(b+c\right)}+\frac{1}{b^3\left(c+a\right)}+\frac{1}{c^3\left(a+b\right)}\ge\frac{3}{2}\)
cho a3+b+c=3abc và abc#0 và a+b+c#0
cmr P=(\(\frac{1}{a}+\frac{1}{b}\))\(\left(\frac{1}{b}+\frac{1}{c}\right)\left(\frac{1}{c}+\frac{1}{a}\right)\)=\(\frac{8}{abc}\)
Bài 1: Cho a,b,c là đọ dài 3 cạnh của một tam giác. CMR: \(\frac{1}{\sqrt{b+c-a}}+\frac{1}{\sqrt{a+c-b}}+\frac{1}{\sqrt{a+b-c}}\ge\frac{1}{\sqrt{a}}+\frac{1}{\sqrt{b}}+\frac{1}{\sqrt{c}}.\)
Bài 2: Cho a,b,c >0. CMR: \(abc\ge\left(a+b-c\right)\left(b+c-a\right)\left(a+c-b\right).\)
Cho a,b,c>0
CMR \(\left(1+\frac{a}{b}\right)\left(1+\frac{b}{c}\right)\left(1+\frac{c}{a}\right)\ge2+\frac{2\left(a+b+c\right)}{\sqrt[3]{abc}}\)
MỌI NGƯỜI GIẢI NHANH GIÙM NHA
Cho a,b,c>0 và abc = 1
CMR:
\(\frac{a+3}{\left(a+1\right)^2}+\frac{b+3}{\left(b+1\right)^2}+\frac{c+3}{\left(c+1\right)^2}\ge3.\\ \)
Cho\(\hept{\begin{cases}a,b,c>0\\abc>1\end{cases}CMR:}2\left(a^2+b^2+c^2\right)+4\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)\ge7\left(a+b+c\right)-3\)