A=(3+3^2)+(3^3+3^4)+....+(3^9+3^10)
= 3.(1+3)+3^3.(1+3)+...+3^9.(1+3)
= 3.4+3^3.4+....+3^9.4
= 4.(3+3^3+....+3^9) chia hết cho 4
=> ĐPCM
k mk nha
\(A=3+3^2+3^3+...+3^9+3^{10}\)10
\(=\left(3+3^2\right)+\left(3^3+3^4\right)+...+\left(3^9+3^{10}\right)\)
\(=3\left(1+3\right)+3^3\left(1+3\right)+...+3^9\left(1+3\right)\)
\(=4\left(3+3^3+...+3^9\right)\) \(⋮4\)