a=(2+1+4).23x........x212
a=7x(23x........x212
suy rA :A CHIA HẾT CHO 7
=(2+2^2+2^3) + (2^4+2^5+2^6)....+(2^10+2^11+2^12)
= 14 + 2^3.14 ...........+ 2^9 .14
=14. (1+2^3+2^9) :7
\(A=2+2^2+2^3+...+2^{12}\)
\(A=\left(2+2^2+2^3\right)+\left(2^4+2^5+2^6\right)+\left(2^7+2^8+2^9\right)+\left(2^{10}+2^{11}+2^{12}\right)\)
\(A=2\left(1+2+2^2\right)+2^4\left(1+2+2^2\right)+2^7\left(1+2+2^2\right)+2^{10}\left(1+2+2^2\right)\)
\(A=2.7+2^4.7+2^7.7+2^{10}.7\)
\(A=7.\left(2+2^4+2^7+2^{10}\right)\)\(⋮\)\(7\)
\(\Rightarrow\)\(A⋮7\)
A = 2 + 2^2 + ........ + 2^12
= 2 * ( 1 + 2 + 2^2 ) +2^4* ( 1 + 2 + 2^2) +......... + 2^10*(1 + 2 + 2^2)
= 2 * 7 + 2^4 * 7 +.....................+ 2^10 * 7
= ( 2 + 2^4 + ...+2^10)*7 chia hết cho 7
=> A chia hết cho 7
A = 2 + 22 + 23 + 24 + 25 + 26 + 27 + 28 + 29 + 210 + 211 + 212
A = ( 2 + 22 + 23 ) + ( 24 + 25 + 26 ) + ( 27 + 28 + 29 ) + ( 210 + 211 + 212 )
A = 2 . ( 1 + 2 + 22 ) + 24 . ( 1 + 2 + 22 ) + 27 ( 1 + 2 + 22 ) + 210 . ( 1 + 2 + 22 )
A = (1 + 2 + 22 ) . ( 2 + 24 + 27 + 210 )
A = 7 . ( 2 + 24 + 27 + 210 ) \(⋮\)7
Vậy A \(⋮\)7