B=196+197/197+198=196/197+198+197/197+198
=>196/197>196/197+198
=>197/198>197?197+198
Vậy A>B
\(A=\frac{196}{197}+\frac{197}{198}\) ; \(B=196+\frac{197}{197}+198\)
Ta có : \(\frac{196}{197}+\frac{197}{198}=1,989873.......\)
\(196+\frac{197}{197}+198=196+1+198=395\)
=> \(A>B\)
\(A=\frac{196}{197}+\frac{197}{198}=\frac{196.198+197.197}{197.198}>1\)
\(B=\frac{196+197}{197+198}=\frac{393}{395}< 1\)
\(\Rightarrow A>B\)